[wxPython-users] Enumerating XML resource names

[Robin Dunn]

Christian Kristukat wrote:
> Eli Golovinsky wrote:
>> If you get the latest pywxrc and XRCed from CVS, you'll be able to use
>> the code generation features there.
>>
>> For each dialog a class is created that contains an attribute for each
>> widget in the dialog.
>>
>>
>> You can find the links to the CVS repository in previous posts or on the
>> wxPython site.
>>
>>
>> If you need some more help, let me know.
> 
> I'm a bit confused what to do with the generated code. With the old approach, I
> load the top level frame which is defined in the xrc file and xrc cares about
> the instantiation and creation of subclassed nodes in the xrc tree. Now, am I
> supposed to subclass the pywxrc generated classes?

Yes.  Of course the old approach still works too, pywxrc is just trying 
to make it easier to use XRC without requiring you to know the necessary 
tricks that make it work.

> How do I finally load the gui
> from the xrc resource?

It is done for you when you call the __init__ method of the base class. 
  For example, here is a module I made for a sample app I used to try 
and reproduce a bug:


import wx
from cbscroll_xrc import xrcFRAME

class FRAME(xrcFRAME):
     def __init__(self):
         xrcFRAME.__init__(self, None)
         self.SPanel.SetVirtualSize(
             self.SPanel.GetSizer().GetMinSize())
         self.SPanel.SetScrollRate(20,20)

app = wx.App(False)
frm = FRAME()
frm.Show()
app.MainLoop()


All of the XRC specific things are in the cbscroll_xrc module and all I 
have to do is derive from xrcFRAME and use it normally.  The self.SPanel 
member was initialized in xrcFRAME.__init__ for me.


-- 
Robin Dunn
Software Craftsman
http://wxPython.org  Java give you jitters?  Relax with wxPython!